Answer: (i) military : Echoes are used from the army locate the fresh gun updates from opponent

Publicat per admin el

Answer: (i) military : Echoes are used from the army locate the fresh gun updates from opponent
If the price out of sound are 334 ms-1, estimate time in that he hears a mirror

  1. military,
  2. geologists,
  3. fishermen.

Answer: t = 0

Radar a tool is utilized locate a challenger heavens-craft vessel. (ii) geologists : Echoes are used from the geologists for mineral lead generation. (iii) fishermen : to find fishes ultrasonic swells is actually sent into liquid. In the event the these types of oscillations hit a seafood, he’s mirrored to the newest receivers. The full time to own hearing this new echoes filed. The position of seafood is computed from the d = v ? t/2 using vel. of sound in water since the 1450 ms -1 .

Matter 1. The new practical application in accordance with the meditation off sound are: (a) megaphone (b) sounding board (c) sonometer (d) each other (a) and (b) Answer: (d) one another (a) and you may (b)

Concern 2. That’s not the condition on development out of echoes ? (a) Lowest length between your source of sound and you can showing system is to feel 17 meters. (b) The warmth of sky can be over 20°C. (c) This new wavelength regarding voice should be less than the latest height from the new highlighting muscles. (d) The fresh new intensity of sound will be sufficient so that it could feel read shortly after reflection. Answer: (a) Minimum distance within supply of sound and you may reflecting human body is become 17 yards.

Matter step 3. To have reading an echo, minimal length between the source of voice and you will highlighting human body is going to be (a) 12 yards (b) twenty four yards (c) 17 m (d) 51 m Answer: (c) 17m

Concern 4. To acquire the victim throughout the dark this new owl or the bat produces: (a) infrasonic surf (b) ultrasonic surf (c) sonic surf (d) infrared surf Address: (b) ultrasonic waves

Question step 1. A man fireplaces a tool facing a building 167 yards aside. Answer: d = 167 ? 2d = 167 ? 2 meters Rates regarding sound = 334 ms -step one t for reflect to get heard = ?

Question dos. An echo try read just after 0.8 s, when one fireplaces an effective cracker, 132.8 meters out-of a leading building. Determine the rate off sound. 8 s d = 132.8 yards

Matter 3. The rate out-of voice try 310 ms -step one . A person fireplaces a weapon. An echo is actually heard once step 1.5 s. Determine the exact distance from people in the cliff at which mirror was read. Answer: Speed regarding sound = 310 ms -1 time right after which reflect was heard t = http://www.datingmentor.org/escort/odessa/ 1.5 s length out of cliff d = ? 2d = Rates ? t

Question step 1. An echo was heard by good radar in 0.08 s. If speed regarding radio surf was 3 ? 10 8 ms -1 , what lengths is the enemy airplanes ? 08 s v = step 3 ? 108 ms -step 1

Question 2. An opponent jet is at a radius out-of 300 kilometres of an effective radar. In the manner far orange new radar should be able to position the newest flat ? Bring acceleration out of radiowaves because 3 ? ten 8 ms -step 1 . Answer: d=3 hundred t = ? v = step 3 ? ten 8 ms -1 t=2d/v = dos ? 300 ? 1000m/3 ?ten 8 ms -1 =0.002 s = 2 ? ten -step 3 s

Question 1. A man stands in between two parallel cliffs and explodes a cracker. He hears the first echo after 0.6 s and second echo after 2.4 s. Calculate the distance between the cliffs. [Speed of sound is 336 ms -1 ] Answer: Let the 2 buildings A and B situated at a distance d1 and d2 from a man’s point.


0 comentaris

Deixa un comentari

L'adreça electrònica no es publicarà. Els camps necessaris estan marcats amb *